Regex - Search and Replace All Digits

Questions & Suggestions
1

I have this that replaces all digits in a string but I need it to not delete the digit in 3rd but all of the other digits.

The 3rd will always be a digit followed by 2 alpha. (3rd, 1st, 2nd etc) but I still want it to delete the other numbers. They can be any digit number from 1 to 99999.

The output for this example should 3rd.

Regex - Search and Replace all Digits copy.kmmacros (3.5 KB)

Keyboard Maestro Export
Keyboard Maestro Export1330×1498 264 KB

Thanks
Roger

2

If you want to match any number that isn't an ordinal, use a negative lookahead and end on a word boundary:

\d+(?!(st|nd|rd|th))\b

"One more more digits that that aren't immediately followed by 'st', 'nd', 'rd' or 'th', and then a word boundary"

So

I am 5556 and the 1st of May 1999

would transform to

I am  and the 1st of May

Note the double space in the middle and the trailing space at the end that you might need to deal with.

Example:

Delete Numbers that Aren't Ordinals.kmmacros (3.1 KB)

Image

Delete Numbers that Aren't Ordinals
Delete Numbers that Aren't Ordinals914×1466 164 KB

This may not be the best method, but it's working in my tests. Looking forward to what others may suggest!

1 Like
3

Gauntlet retrieved, @Nige_S. I'd just look for digits and a word boundary to avoid ordinals:

\d+\b

But then I wonder if that's sufficient. Probably for list of names. But I'd be more comfortable with a more comprehensive spec. You might prefer looking for numbers at the end of a line:

\b\d+$

And whitespace may or may not have to be dealt with.

2 Likes
4

Yes -- that's much better! (Note to self: stop overcomplicating things.)

Agreed. We might even want to start with a \b as well, on the off-chance someone's GivenName is "R2D2" :wink:

2 Likes